PTS Semester 2
LATIHAN
• 1/10
No. 1
Lapor
Dua segitiga
A
B
C
ABC
A
BC
dan
D
E
F
DEF
D
EF
kongruen. Jika panjang
A
B
=
E
F
=
10
AB = EF = 10
A
B
=
EF
=
10
cm,
B
C
=
D
F
=
12
BC = DF = 12
BC
=
D
F
=
12
cm, dan
A
C
=
D
E
=
14
AC = DE = 14
A
C
=
D
E
=
14
cm, maka pasangan sudut yang sama besar adalah...
A
∠
A
=
∠
D
\angle A = \angle D
∠
A
=
∠
D
B
∠
B
=
∠
E
\angle B = \angle E
∠
B
=
∠
E
C
∠
C
=
∠
F
\angle C = \angle F
∠
C
=
∠
F
D
∠
A
=
∠
E
\angle A = \angle E
∠
A
=
∠
E
Sebelumnya
Selanjutnya