Bab 4: Unsur Radioaktif
LATIHAN
• 1/5
No. 1
Lapor
Isotop
11
22
N
a
^ {22}_{11}Na
11
22
N
a
meluruh melalui emisi positron. Tuliskan persamaan reaksi peluruhannya dan identifikasi produk yang terbentuk.
A
A.
11
22
N
a
→
12
22
M
g
+
−
1
0
e
^ {22}_{11}Na \rightarrow ^ {22}_{12}Mg + ^0_{-1}e
11
22
N
a
→
12
22
M
g
+
−
1
0
e
(Magnesium-22)
B
B.
11
22
N
a
→
10
22
N
e
+
+
1
0
e
^ {22}_{11}Na \rightarrow ^ {22}_{10}Ne + ^0_{+1}e
11
22
N
a
→
10
22
N
e
+
+
1
0
e
(Neon-22)
C
C.
11
22
N
a
→
11
21
N
a
+
0
1
n
^ {22}_{11}Na \rightarrow ^ {21}_{11}Na + ^1_0n
11
22
N
a
→
11
21
N
a
+
0
1
n
(Natrium-21)
D
D.
11
22
N
a
→
10
21
N
e
+
1
1
H
^ {22}_{11}Na \rightarrow ^ {21}_{10}Ne + ^1_1H
11
22
N
a
→
10
21
N
e
+
1
1
H
(Neon-21)
E
E.
11
22
N
a
→
12
23
M
g
+
−
1
0
e
^ {22}_{11}Na \rightarrow ^ {23}_{12}Mg + ^0_{-1}e
11
22
N
a
→
12
23
M
g
+
−
1
0
e
(Magnesium-23)
Sebelumnya
Selanjutnya