Bab 6: Integral Tentu
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• 1/5
No. 1
Lapor
Jika
F
(
x
)
=
∫
1
x
2
t
3
+
1
d
t
F(x) = \int_1^{x^2} \sqrt{t^3 + 1} dt
F
(
x
)
=
∫
1
x
2
t
3
+
1
d
t
, maka
F
′
(
x
)
F'(x)
F
′
(
x
)
adalah...
A
A.
x
6
+
1
\sqrt{x^6 + 1}
x
6
+
1
B
B.
2
x
x
6
+
1
2x\sqrt{x^6 + 1}
2
x
x
6
+
1
C
C.
1
2
x
3
+
1
\frac{1}{2\sqrt{x^3 + 1}}
2
x
3
+
1
1
D
D.
x
2
x
6
+
1
x^2\sqrt{x^6 + 1}
x
2
x
6
+
1
E
E.
2
x
2
x
6
+
1
2x^2\sqrt{x^6 + 1}
2
x
2
x
6
+
1
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