Bab 5: Turunan Trigonometri
LATIHAN
• 1/5
No. 1
Lapor
Jika
y
=
sin
x
1
+
cos
x
y = \frac{\sin x}{1 + \cos x}
y
=
1
+
c
o
s
x
s
i
n
x
, buktikan bahwa
y
′
=
1
1
+
cos
x
y' = \frac{1}{1 + \cos x}
y
′
=
1
+
c
o
s
x
1
.
A
1
−
sin
x
(
1
+
cos
x
)
2
\frac{1 - \sin x}{(1 + \cos x)^2}
(
1
+
c
o
s
x
)
2
1
−
s
i
n
x
B
cos
x
(
1
+
cos
x
)
2
\frac{\cos x}{(1 + \cos x)^2}
(
1
+
c
o
s
x
)
2
c
o
s
x
C
1
1
+
cos
x
\frac{1}{1 + \cos x}
1
+
c
o
s
x
1
D
sin
x
(
1
+
cos
x
)
2
\frac{\sin x}{(1 + \cos x)^2}
(
1
+
c
o
s
x
)
2
s
i
n
x
E
−
sin
x
1
+
cos
x
\frac{-\sin x}{1 + \cos x}
1
+
c
o
s
x
−
s
i
n
x
Sebelumnya
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