Bab 8: Integral Tak Tentu
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• 1/5
No. 1
Lapor
Hasil dari
∫
(
x
−
1
)
2
x
d
x
\int (x-1)^2 x dx
∫
(
x
−
1
)
2
x
d
x
adalah...
A
1
4
x
4
−
2
3
x
3
+
1
2
x
2
+
C
\frac{1}{4}x^4 - \frac{2}{3}x^3 + \frac{1}{2}x^2 + C
4
1
x
4
−
3
2
x
3
+
2
1
x
2
+
C
B
1
4
x
4
−
x
3
+
x
2
+
C
\frac{1}{4}x^4 - x^3 + x^2 + C
4
1
x
4
−
x
3
+
x
2
+
C
C
1
4
x
4
−
1
3
x
3
+
1
2
x
2
+
C
\frac{1}{4}x^4 - \frac{1}{3}x^3 + \frac{1}{2}x^2 + C
4
1
x
4
−
3
1
x
3
+
2
1
x
2
+
C
D
1
3
(
x
−
1
)
3
⋅
1
2
x
2
+
C
\frac{1}{3}(x-1)^3 \cdot \frac{1}{2}x^2 + C
3
1
(
x
−
1
)
3
⋅
2
1
x
2
+
C
E
1
3
(
x
−
1
)
3
+
C
\frac{1}{3}(x-1)^3 + C
3
1
(
x
−
1
)
3
+
C
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